Motion in a Plane

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Question : 14
Total: 32
In a harbour, wind is blowing at the speed of 72 km h1 and the flag on the mast of a boat anchored in the harbour flutters along the N-E direction. If the boat starts moving at a speed of 51 km h1 to the north, what is the direction of the flag on the mast of the boat?
Solution:  
When the boat is anchored in the harbour, the flag flutters along the N-E direction. It shows that the velocity of wind is along the north-east direction. When the boat starts moving, the flag will flutter along the direction of relative velocity of wind w.r.t. boat. Let
v
wb
be the relative velocity of wind w.r.t. boat and β be the angle between
v
wb
and
v
w
. Refer Fig.
Now,
v
wb
=
v
w
+(
v
b
)

Here, |
v
w
|
=72kmh1

|
v
b
|
=51kmh1

Angle between
v
w
and
v
b
is 135° i.e. θ=135°.
Then
tanβ=
51sin135°
72+51cos135°

=
51sin45°
72+51(cos45°)

=
51×
1
2
7251(
1
2
)
=1.0039

β=tan1(1.0039)=45.1°
Angle w.r.t. east direction =45.1°45°=0.1°
It means the flag will flutter almost due east.
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