Motion in a Straight Line
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Question : 3
Total: 27
A woman starts from her home at 9.00 am, walks with a speed of 5 km h– 1 – 1
Solution:
From home to office : Time at which she leaves home for the office= 9 am
speed= 5 k m h − 1 ; = 2.5 k m
Therefore, time taken to reach the office,
t =
=
= 0.5 h = 30 m i n
Thus, time at which she reaches her office = 9.30 am.
Between 9.30 am to 5 pm, she remains in her office i.e. at a distance of 2.5 km from her home.
From office to home : Time at which she leaves her office = 5 pm.
Speed= 25 k m h − 1 , = 2.5 k m
Therefore, time taken to reach the home,t =
=
h = 6 m i n
Therefore, time at which she reaches her home = 5.06 pm.
Hence, (x-t) graph of her motion will be as shown in figure.
speed
Therefore, time taken to reach the office,
Thus, time at which she reaches her office = 9.30 am.
Between 9.30 am to 5 pm, she remains in her office i.e. at a distance of 2.5 km from her home.
From office to home : Time at which she leaves her office = 5 pm.
Speed
Therefore, time taken to reach the home,
Therefore, time at which she reaches her home = 5.06 pm.
Hence, (x-t) graph of her motion will be as shown in figure.
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