Units and Measurement
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Question : 15
Total: 33
A famous relation in physics relates ‘moving mass’ m to the ‘rest mass’ mo of a particle in terms of its speed v and the speed of light, c. (This relation first arose as a consequence of special theory of relativity due to Albert Einstein). A boy recalls the relation almost correctly but forgets where to put the constant c. He writes :
m = m o ( 1 − v 2 ) 1 ∕ 2
Guess where to put the missing c.
Guess where to put the missing c.
Solution:
From principle of homogenetity of dimensions both sides ofabove formula must be same dimensions. For this, ( 1 – v 2 ) 1 ∕ 2
Therefore, instead of ( 1 − v 2 ) 1 ∕ 2 , ( 1 − v 2 ∕ c 2 ) 1 ∕ 2
Hence relation should be
Therefore, instead of
Hence relation should be
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