Work, Power and Energy

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Question : 15
Total: 30
A pump on the ground floor of a building can pump up water to fill a tank of volume 30 m3 in 15 min. If the tank is 40 m above the ground, and the efficiency of the pump is 30%, how much electric power is consumed by the pump.
Solution:  
As given that
Volume of water =30m3
Time taken by pump to fill tank =15min=15×60=900s
The height of tank = 40 m
The efficiency of pump = 30%
Consumption of power by pump = ?
Mass of water pumped = Volume × density =30×103 (Density of water =103kgm3)
Output power, P0=
W
t
=
mgh
t
=
30×103×9.8×40
900
=13070 watt
Pi is required power (input power), then efficiency η=
P0
Pi

Pi=
P0
η
=
13070
30
100
=43567watt
= 43.567 kW
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