Work, Power and Energy

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Question : 18
Total: 30
The bob of a pendulum is released from a horizontal position. If the length of the pendulum is 1.5 m, what is the speed with which the bob arrives at the lowermost point, given that it dissipated 5% of its initial energy against air resistance?
Solution:  
Length of pendulum h = 1.5 m
Let m be mass of the bob, then potential energy of the bob at A,
mgh=m×9.8×1.5J
On reaching the lowest point B, the bob will acquire an equal amount ofkinetic energy. But as 5% of energy is lost against the air friction.
Energy converted =95%(mgh)
If v is the velocity acquired by the bob at the point B, then
K.E.=
1
2
m
v2
=
95
100
mgh

v=
95
100
×2
×gh
=
19
20
×2
×9.8
×1.5
=5.285ms1
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