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NCERT Class XII Chapter
Alternating Current
Questions With Solutions

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Question : 19
Total: 26
Suppose the circuit in Q. 18 has a resistance of 15 Ω. Obtain the average power transferred to each element of the circuit and the total power absorbed.
Solution:  

If the circuit has a resistance of 15 Ω, now it is LCR series resonant circuit.
Now the impedance,
Z = √R2+(XL−XC)2
Z = √152+(27.93)2 = 31.7 Ω
Virtual current, Iv =
Ev
Z
 =
230
31.7
 = 7.26 A
Average power transferred to ‘L’,
PL = IvEv cos π/2 = 0
Average power transferred to ‘C’,
PC = EvIv cos π/2 = 0
Average power transferred to ‘R’,
PR = VRIv cos 0°
PR = (IvR)Iv = Iv2 R = (7.26)2 × 15 = 791 W
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