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NCERT Class XII Chapter
Alternating Current
Questions With Solutions

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Question : 24
Total: 26
At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is 100 m3s–1. If the turbine generator efficiency is 60%, estimate the electric power available from the plant (g = 9.8 ms–2).
Solution:  
Workdone by liquid pressure = pressure × volume shifted power of flowing water
Hydro-power =
Work
time
 = pressure ×
volume
time
Hydro-power = hρg × (V/t) = 300 × 103 × 9.8 × 100 = 29.4 × 107 Watt
Efficiency of turbine η =
Electric‌power
Hydro−power
 ⇒ 0.6 =
Electric‌power
29.4×107
Electric power = 0.6 × 29.4 × 107 = 176.4 × 106 W = 176.4 MW
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