NCERT Class XII Chapter
Electrostatic Potential and Capacitance
Questions With Solutions
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Question : 20
Total: 37
Two charged conducting spheres of radii a and b are connected to each other by a wire. What is the ratio of electric fields at the surfaces of the two spheres? Use the result obtained to explain why charge density on the sharp and pointed ends of a conductor is higher than on its flatter portions.
Solution:
As the two spheres are connected to each other by wire, so they have same electric potential i.e., V a V b
or
q q
So, the ratio of electric fields at the surfaces of the two spheres is
×
If b > a, thenE a E b
i.e. sphere with smaller radius produces more electric field on its surface. Hence, the charge density on the sharp and pointed ends of conductor is higher than on its flatter portions.
or
So, the ratio of electric fields at the surfaces of the two spheres is
If b > a, then
i.e. sphere with smaller radius produces more electric field on its surface. Hence, the charge density on the sharp and pointed ends of conductor is higher than on its flatter portions.
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