NCERT Class XII Chapter
Electrostatic Potential and Capacitance
Questions With Solutions
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Question : 31
Total: 37
Answer carefully:
(a) Two large conducting spheres carrying chargesQ 1 Q 2
(b) If coulomb’s law involved 1/r 3 r 2
(c) A small test charge is released at rest at a point in an electrostatic field configuration. Will it travel along the field line passing through that point?
(d) What is the work done by the field of a nucleus in a complete circular orbit of the electron? What if the orbit is elliptical?
(e) We know that electric field is discontinuous across the surface of a charged conductor. Is electric potential also discontinuous there?
(f) What meaning would you give to the capacitance of a single conductor?
(g) Guess a possible reason why water has a much greater dielectric constant (= 80) then say, mica (= 6).
(a) Two large conducting spheres carrying charges
(b) If coulomb’s law involved 1/
(c) A small test charge is released at rest at a point in an electrostatic field configuration. Will it travel along the field line passing through that point?
(d) What is the work done by the field of a nucleus in a complete circular orbit of the electron? What if the orbit is elliptical?
(e) We know that electric field is discontinuous across the surface of a charged conductor. Is electric potential also discontinuous there?
(f) What meaning would you give to the capacitance of a single conductor?
(g) Guess a possible reason why water has a much greater dielectric constant (= 80) then say, mica (= 6).
Solution:
(a) No, because coulomb’s law holds good only for point charges.
(b) No, because in that case electric flux linked with the closed surface will also become dependent on ‘r’ other than charge enclosed by it.
(c) No, it will travel along the field line only if it is a straight line.
(d) Zero, whatever may be the shape of orbit may be. It is because work done in moving a charge in closed path in electric field is zero, as electric field is a conservative field.
(e) No, electric potential is continuous there. As E = 0, so
(f) It means that a single conductor is a capacitor whose other plate can be considered to be at infinity.
(g) A water molecule is a polar molecule with non-zero electric dipole moment, however mica does not have polar molecules. So, dielectric constant of water is high.
(b) No, because in that case electric flux linked with the closed surface will also become dependent on ‘r’ other than charge enclosed by it.
(c) No, it will travel along the field line only if it is a straight line.
(d) Zero, whatever may be the shape of orbit may be. It is because work done in moving a charge in closed path in electric field is zero, as electric field is a conservative field.
(e) No, electric potential is continuous there. As E = 0, so
(f) It means that a single conductor is a capacitor whose other plate can be considered to be at infinity.
(g) A water molecule is a polar molecule with non-zero electric dipole moment, however mica does not have polar molecules. So, dielectric constant of water is high.
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