NCERT Class XII Chapter
Electrostatic Potential and Capacitance
Questions With Solutions
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Question : 9
Total: 37
Explain what would happen if in the capacitor given in above question, a 3 mm thick mica sheet (of dielectric constant = 6) were inserted between the plates.
(a) While the voltage supply remained connected.
(b) After the supply was disconnected.
(a) While the voltage supply remained connected.
(b) After the supply was disconnected.
Solution:
C = K C 0
(a) If the voltage supply remained connected, then the potential difference across the capacitor will remain the same i.e. V = 100 V and hence charge on the capacitor becomes
Q = CV = 108 ×10 – 12 10 – 8
(b) If the voltage supply was disconnected, then charge on the capacitor remains the same
i.e., Q = 1.8 ×10 − 9
and hence potential difference across the capacitor becomes
V =
(a) If the voltage supply remained connected, then the potential difference across the capacitor will remain the same i.e. V = 100 V and hence charge on the capacitor becomes
Q = CV = 108 ×
(b) If the voltage supply was disconnected, then charge on the capacitor remains the same
i.e., Q = 1.8 ×
and hence potential difference across the capacitor becomes
V =
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