NCERT Class XII Chapter
Magnetism and Matter
Questions With Solutions
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Question : 3
Total: 25
A short bar magnet placed with its axis at 30° with a uniform external magnetic field of 0.25 T experiences a torque of magnitude equal to 4.5 × 10 – 2 J. What is the magnitude of magnetic moment of the magnet?
Solution:
Torque τ = MB sinθ
4.5 ×10 – 2 = M (0.25 sin 30°)
Magnetic dipole moment, M = 0.36 JT – 1 .
4.5 ×
Magnetic dipole moment, M = 0.36 J
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