NCERT Class XII Chapter
Magnetism and Matter
Questions With Solutions

© examsnet.com
Question : 9
Total: 25
A circular coil of 16 turns and radius 10 cm carrying a current of 0.75 A rests with its plane normal to an external field of magnitude 5.0 × 102 T. The coil is free to turn about an axis in its plane perpendicular to the field direction. When the coil is turned slightly and released, it oscillates about its stable equilibrium with a frequency of 2.0 s1. What is the moment of inertia of the coil about its axis of rotation?
Solution:  
The circular coil carries a dipole moment
M = NIA = 16 × 0.75 × π [0.1]2 = 0.3768 A-m2
Time period of oscillation, T = 2π
I
MB


Frequency f =
1
2π
MB
I

So, moment of inertia I =
1
4π2
MB
f2

I =
1
4π2
×
(0.3768)×5×102
(2)2
= 11.9 × 105 kg m2
© examsnet.com
Go to Question: