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NCERT Class XII Chemistry
Chapter - Coordination Compounds
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Question : 41 of 43
Marks: +1, -0
Predict the number of unpaired electrons in the square planer [Pt(CN)4]2–[Pt(CN)_4] ^{2–} ion.
Solution:  
For square planer shape, the hybridisation is dsp2^{2}. Hence, theunpaired electrons in 5d orbital pair up to make one d-orbital empty fordsp2^{2}hybridisation. Thus there is no unpaired electron.
[Pt(CN)4]2–:Pt(78):6s15d9,[Pt(CN)_4]_2– : Pt(78) : 6s^{1}5d^{9} ,
Pt2+:6s05d8Pt^{2+} : 6s^{0}5d^{8}
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