NCERT Class XII Chemistry
Chapter - Electrochemistry
Questions with Solutions
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Question : 2
Total: 32
Given the standard electrode potentials,
K+ /K = –2.93 V, Ag+ /Ag = 0.80 V, Hg2 + /Hg = 0.79 V, Mg2 + /Mg = –2.37 V, Cr3 + /Cr = – 0.74 V
Arrange these metals in their increasing order of reducing power.
K
Arrange these metals in their increasing order of reducing power.
Solution:
Higher the oxidation potential, more easily it is oxidized and hence greater is the reducing power. Thus, increasing order of reducing power will be
Ag < Hg < Cr < Mg < K.
Ag < Hg < Cr < Mg < K.
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