NCERT Class XII Chemistry
Chapter - Electrochemistry
Questions with Solutions

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Question : 2
Total: 32
Given the standard electrode potentials,
K+/K = –2.93 V, Ag+/Ag = 0.80 V, Hg2+/Hg = 0.79 V, Mg2+/Mg = –2.37 V, Cr3+/Cr = – 0.74 V
Arrange these metals in their increasing order of reducing power.
Solution:  
Higher the oxidation potential, more easily it is oxidized and hence greater is the reducing power. Thus, increasing order of reducing power will be
Ag < Hg < Cr < Mg < K.
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