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NCERT Class XII Chemistry
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Question : 27 of 53
Marks: +1, -0
If the solubility product of CuS is 6 × 10 −16^{-16}, calculate the maximum molarity of CuS in aqueous solution.
Solution:  
Maximum molarity of CuS in aqueous solution = Solubility of CuSin mol L−1\mathrm{mol}\,\mathrm{L}^{-1}
If S is the solubility of CuS in mol L−1\mathrm{mol}\,\mathrm{L}^{-1} , then
CuS⇌Cu2++S2−\mathrm{CuS} \rightleftharpoons \mathrm{Cu}^{2+} + \mathrm{S}^{2-}, Ksp=[Cu2+][S2−]K_{sp} = [\mathrm{Cu}^{2+}] [\mathrm{S}^{2-}] =S×S=S2= S \times S = S^2
∴    S2=6×10−16\therefore\;\; S^2 = 6 \times 10^{-16} or S=6×10−16S = \sqrt{6 \times 10^{-16}} =2.45×10−8  mol  L−1= 2.45 \times 10^{-8} \; \mathrm{mol} \; \mathrm{L}^{-1}
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