NCERT Class XII Chemistry
Chapter - Solutions
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Question : 24
Total: 53
Based on solute-solvent interactions, arrange the following in order of increasing solubility in n-octane and explain.
Cyclohexane, KCl, CH3 OH, CH3 CN
Cyclohexane, KCl, CH
Solution:
(i) Cyclohexane and n-octane both are non-polar. Hence, they mix completely in all proportions.
(ii) KCl is an ionic compound while n-octane is non-polar. Hence, KCl will not dissolve at all in n-octane.
(iii) CH3 OH and CH3 CN both are polar but CH3 CN is less polar than CH3 OH. As the solvent is non-polar, CH3 CN will dissolve more than CH3 OH in n-octane.
Thus, the order of solubility will be KCl < CH3 OH < CH3 CN < Cyclohexane.
(ii) KCl is an ionic compound while n-octane is non-polar. Hence, KCl will not dissolve at all in n-octane.
(iii) CH
Thus, the order of solubility will be KCl < CH
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