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NCERT Class XII Chemistry
Chapter - The Solid State
Questions with Solutions

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Question : 10 of 50
Marks: +1, -0
Calculate the efficiency of packing in case of a metal crystal for
(i) simple cubic
(ii) face-centred cubic (with the assumptions that atoms are touching each other).
(iii) body-centred cubic
Solution:  
(i) In a simple cubic unit cell :
Suppose the edge length of the unit cell = a and radius of the sphere = r
As spheres are touching each other, evidently, a=2ra = 2r
No. of spheres per unit cell =18×8=1= \frac{1}{8} \times 8 = 1
Volume of the sphere =43Ï€r3= \frac{4}{3} \pi r^{3}
Volume of the cube =a3=(2r)3=8r3= a^{3} = (2r)^{3} = 8 r^{3}
therefore\text{therefore} Fraction occupied. , i.e.,\text{, i.e.,} packing fraction =(43πr3)= \left( \frac{4}{3} \pi r^{3} \right) / 8r3=0.5248 r^{3} = 0.524
or % occupied i.e.,\text{i.e.,} packing efficiency = 52.4%
(ii) In face-centred cubic structure : As sphere on the face-centre is touching the spheres at the corners, evidently AC=4r.AC = 4r.
But from right angled triangle ABC, AC=AB2+BC2AC = \sqrt{AB^{2} + BC^{2}}
        =a2+a2=2a\;\;\;\;= \sqrt{a^{2}+a^{2}} = \sqrt{2} a
∴    2a=4r\therefore\;\;\sqrt{2a = 4r} or a=42ra = \frac{4}{\sqrt{2}} r
∴    \therefore\;\; Volume of the unit cell =a3=(42r)3=322r3= a^{3} = \left( \frac{4}{\sqrt{2}} r \right)^{3} = \frac{32}{\sqrt{2}} r^{3}
No. of spheres in the unit cell =8×18+6×12=4= 8 \times \frac{1}{8} + 6 \times \frac{1}{2} = 4
Volume of four spheres =4×43πr3=163πr3= 4 \times \frac{4}{3} \pi r^{3} = \frac{16}{3} \pi r^{3}
∴ Fraction occupied i.e., packing fraction =16πr3332r32=0.74= \frac{ \frac{16 \pi r^{3}}{3} }{ \frac{32 r^{3}}{\sqrt{2}} } = 0.74
or % occupied i.e.,\text{i.e.,} packing efficiency = 74%
(iii) In body-centred cubic structure : As the sphere at the body-centre touches the spheres at the corners, body diagonal, AD=4r.AD = 4r.
Further, face diagonal,
AC=AB2+BC2=a2+a2=2aAC = \sqrt{AB^{2} + BC^{2}} = \sqrt{a^{2} + a^{2}} = \sqrt{2} a
and body diagonal,
AD=AC2+CD2=2a2+a2=3aAD = \sqrt{AC^{2} + CD^{2}} = \sqrt{2a^{2} + a^{2}} = \sqrt{3} a
∴      3a=4r\therefore\;\;\;\sqrt{3} a = 4 r
or a=4r3a = \frac{4r}{\sqrt{3}}
∴      \therefore\;\;\; Volume of the unit cell =a3=(4r3)3=64r333= a^{3} = \left( \frac{4r}{\sqrt{3}} \right)^{3} = \frac{64 r^{3}}{3 \sqrt{3}}
No. of spheres per unit cell =8×18+1=2= 8 \times \frac{1}{8} + 1 = 2
Volume of two spheres =2×43πr3=83πr3= 2 \times \frac{4}{3} \pi r^{3} = \frac{8}{3} \pi r^{3}
therefore\text{therefore} Fraction occupied i.e., packing fraction =83Ï€r364r333=0.68= \frac{ \frac{8}{3} \pi r^{3} }{ \frac{64 r^{3}}{3 \sqrt{3}} } = 0.68
or % occupied i.e\text{i.e} ., packing efficiency = 68%
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