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NCERT Class XII Chemistry
Chapter - The Solid State
Questions with Solutions

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Question : 16 of 50
Marks: +1, -0
Analysis shows that nickel oxide has the formula Ni0.98_{.98}O1.00_{1.00}. What fractions of nickel exist as Ni2+^{2+} and Ni3+^{3+} ions?
Solution:  
98 Ni-atoms are associated with 100 O-atoms. Out of 98 Ni-atoms,
suppose Ni present as Ni2+^{2+} = xx
Then Ni present as Ni3+^{3+ }= 98x98 - x
Total charge on x Ni2+^{2+} and (98 – x) Ni3+^{3+} should be equal to charge on 100 O2^{2-} ions.
Hence, x×2+(98x)×3=100×2x \times 2 + (98 - x) \times 3 = 100 \times 2
or 2x+2943x=2002x + 294 - 3x = 200 or x=94x = 94
    \therefore\;\; Fraction of Ni{\mathrm{Ni}} present as Ni2+=9498×100=96%{\mathrm{Ni}}^{2+} = \frac{94}{98} \times 100 = 96\%
Fraction of Ni present as Ni3+=498×100=4%{\mathrm{Ni}}^{3+} = \frac{4}{98} \times 100 = 4\%
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