NCERT Class XII Mathematics Chapter - - Solutions

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Question : 67
Total: 101
Suppose that two cards are drawn at random from a deck of cards. Let X be the number of aces obtained. Then the value of E(X) is
Solution:  
X denote the random variable which assume the number of aces obtained
∴ X can assume values 0, 1 and 2.
∴ P(X = 0) = P (No ace) =
48C2
52C2
=
48×47
52×51
=
1128
1326

P(X = 1) = P (one ace) =
4C1×48C1
52C2
=
4×48
52×51
=
192
1326

P(X = 2) = P (two aces) =
4C2
52C2
=
4×3
52×51
=
6
1326

Hence the probability distribution is :
 X  0  1  2
 P(X)  
1128
1326
 
192
1326
 
6
1326
E(X)=XP(X) =0×
1128
1326
+1×
192
1326
+2×
6
1326
=
2
13
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