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AFCAT I 2015 Solved Paper
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© examsnet.com
Question : 37
Total: 100
A train travelling at a uniform speed clears a platform 200 m long in 10 seconds and passes a telegraph post in 5 seconds.The speed of the train is
36 km/h
39 km/h
72 km/h
144 km/h
Validate
Solution:
Speed = distance\/time
1
k
m
∕
h
r
=
5
∕
18
m
∕
s
e
c
1
m
∕
s
e
c
=
18
∕
5
k
m
∕
h
r
Let speed of train be
x
m
∕
s
e
c
and length of train be
y
m
, then According to the question
x
=
(
200
+
y
)
10
−
(
1
)
x
=
y
5
−
(
2
)
From equation (1) and equation (2)
y
5
=
(
200
+
y
)
10
⇒
2
y
=
200
+
y
⇒
2
y
−
y
=
200
⇒
y
=
200
Length of train is 200 m
From equation (2)
x
=
200
5
⇒
x
=
40
m
∕
s
e
c
⇒
x
=
40
×
18
5
⇒
x
=
144
k
m
∕
h
r
∴
Speed of train is
144
k
m
∕
h
r
.
© examsnet.com
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