AFCAT I 2020 Solved Paper

Let cost of first article be x then cost of second article will be $560 - x$ Profit percent on first is =$x \times \frac{10}{100}$ loss percent on second is = $(560 - x) \times \frac{15}{100}$ Because profit = loss we can equate above $\Rightarrow x \times \frac{10}{100}$= $(560 - x) \times \frac{15}{100}$ $\Rightarrow \frac{x}{10} = (560 - x) \times \frac{3}{20}$ Multiply both sides of the equation by 20, the least common multiple of 10,20. $2 x = 20(560 - x) \times \left( \; \frac{3}{20} \right)$ $2 x = 3(560 - x)$ Use the distributive property to multiply 3 by $560 - x$ $2 x = 1680 - 3 x$ Add $3 x$ to both sides. $2 x + 3 x = 1680$ Combine $2 x$ and $3 x$ to get $5 x$ $5 x = 1680$ ⇒ x = 336 and second article is 560-336 = 224