Given that A+B+C=5625⋅⋅⋅⋅⋅⋅⋅(i) According to the question A=(B+C)∕2 ⇒B+C=2A Adding A on both sides ⇒A+B+C=3A=5625[ from (1) ] ⇒3A=5625 ⇒A= Rs. 1875 Again B=(A+C)∕4 ⇒A+C=4B ⇒A+B+C=5B=5625[ from (1)] ⇒5B=5625 ⇒B=Rs.1125 ⇒A−B=1875−1125=750 ∴ A's share is more than that of B by Rs. 750 .