AFCAT Model Paper 1

Given: Arun takes out 25% of the total chocolates From reamaining, Rahul takes out 100 chocolates From remaining, Ramesh takes out 50% of chocolates At last number of chocolates in the box = 100 Calculation: Let the number of chocolates initially present in the box be x. Arun takes out 25% of the chocolates ⇒ Remaing chocolates = x - 25% of x ⇒ $x - \frac{x}{4} = \frac{3x}{4}$ Now, Rahul takes out 100 chocolates ⇒ Remaining chocolates $= \left(\frac{3x}{4} - 100\right)$ Now, Ramesh takes out 50% of the chocolates ⇒ Remaining chocolates $= \frac{\left(\frac{3x}{4} - 100\right)}{2}$ Now, According to the question At last remaining chocolates = 100 ⇒ $\frac{\left(\frac{3x}{4} - 100\right)}{2} = 100$ ⇒ $\left(\frac{3x}{4} - 100\right) = 200$ ⇒ $\frac{3x}{4} = 300$ ⇒ x = 400 ∴ The number of chocolates present in the box initially is 400.