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AIIMS 2015 Chemistry Question Paper for free online practice with solutions

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Question : 13

Total: 60

CH3−CH2CH=CH2+HBr

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X and Y respectively are

BrCH2−CH2−CH=CH2 and C2H5−CHBr−CH3
C2H5−CH2−CH2Br and
Br−CH2−CH2−CH=CH2
C_2H_5-CH_2-CH_2BrandC_2H_5-CHBr-CH_3$
C2H5CHBr−CH3 and C2H5−CH2−CH2Br

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