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AIIMS 2015 Chemistry Question Paper for free online practice with solutions

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Question : 36

Total: 60

Formation of polyethylene from calcium carbide takes place is follows:
CaC2+2H2O→Ca(OH)2+C2H2
C2H2+H2→C2H4
nC2H4→−(CH2−CH2)−n
The amount of polyethylene obtained from 64.0 kg of CaC2 is

27 kg
24 kg
22 kg
28 kg

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