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AIIMS 26 May 2019 Morning Question Paper with solutions for online practice
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© examsnet.com
Question : 9
Total: 146
Given
V
C
M
=
2
m
s
,
m
=
2
k
g
,
R
=
4
m
Find angular momentum of ring about origin if it is in pure rolling
32
k
g
m
2
/
s
24
k
g
m
2
/
s
16
k
g
m
2
/
s
8
k
g
m
2
/
s
Validate
Solution:
→
L
=
I
C
M
.
ω
+
m
V
C
M
r
1
d
ω
=
v
R
=
2
4
=
0.5
rad/sec
→
L
=
M
R
2
⋅
ω
+
M
V
C
M
⋅
R
=
2
×
16
×
0.5
+
2
×
2
×
4
=
16
+
16
→
L
=
32
k
g
×
m
2
s
© examsnet.com
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