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AIPMT 2000 Physics and Chemistry Paper
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© examsnet.com
Question : 10
Total: 100
A body of weight 72 N moves from the surface of earth at a height half of the radius of the earth, then gravitational force exerted on it will be :
36 N
32 N
144 N
50 N
Validate
Solution:
F
=
m
g
=
72
N
g
′
=
g
(
R
e
R
e
+
h
)
2
=
g
(
R
e
R
e
+
R
e
∕
2
)
2
=
g
[
2
R
e
3
R
e
]
2
=
4
9
g
F
′
=
m
g
′
=
m
g
×
4
9
=
72
×
4
9
=
32
N
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