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AIPMT 2008 Physics and Chemistry Paper
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© examsnet.com
Question : 16
Total: 100
A thin rod of length
L
and mass
M
is bent at its midpoint into two halves so that the angle between them is
90
∘
. The moment of inertia of the bent rod about an axis passing through the bending point and perpendicular to the plane defined by the two halves of the rod is -
ML
2
6
√
2
ML
2
24
ML
2
24
ML
2
12
Validate
Solution:
Moment of inertia of the system
I
=
M
(
L
/
2
)
2
3
+
M
(
L
/
2
)
2
3
=
ML
2
12
+
ML
2
12
=
ML
2
6
© examsnet.com
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