The state of hybridization of {\C}_2, {\C}_3, {\C}_5 and {\C}_6 of the hydrocarbon - C_{7}H_3-C↖\stackrel{ \CH_3}{{|}}_{{6|}_{ \CH_3}}-C_{5}H=C_{4}H-C^{|↖{ \CH_3}}H-C_{2}=C_{1}H is in the following sequence :

Correct Answer is : sp,sp3,sp2 and sp3

{sp}, {sp}^2, {sp}^3 and {sp}^2

{sp}, {sp}^3, {sp}^2 and {sp}^3