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AIPMT 2010 Physics and Chemistry Paper
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© examsnet.com
Question : 2
Total: 100
The mass of
a
3
7
Li
nucleus is
0.042
u less than the sum of the masses of all its nucleons. The binding energy per nucleon of
3
7
Li
nucleus is nearly
46
MeV
5.6
MeV
3.9
MeV
23
MeV
Validate
Solution:
For
3
7
Li
nucleus,
Mass defect,
∆
M
=
0.042
u
∴
1
u
=
931.5
MeV
/
c
2
=
39.1
MeV
/
c
2
Binding energy,
E
b
=
∆
Mc
2
=
(
39.1
MeV
c
2
)
c
2
=
39.1
MeV
Binding energy per nucleon,
E
b
n
=
E
b
A
=
39.1
MeV
7
=
5.6
MeV
© examsnet.com
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