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AIPMT 2013 Physics and Chemistry Paper
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© examsnet.com
Question : 41
Total: 90
When a proton is released from rest in a room, it starts with an initial acceleration
a
0
towards west. When it is projected towards north with a speed
v
0
it moves with an initial acceleration
3
a
0
towards west. The electric and magnetic fields in the room are:
ma
0
e
east,
3
ma
0
e
ev
0
down
ma
0
e
west,
2
ma
0
e
ev
0
up
ma
0
e
west,
2
ma
0
e
v
0
down
ma
0
e
east,
3
ma
0
e
ev
0
up
Validate
Solution:
Acceleration of charged particle
→
a
=
q
/
m
(
→
E
+
→
v
×
→
B
)
Released from rest
⇒
→
a
=
q
m
→
E
=
a
0
(west)
⇒
→
E
=
ma
0
e
(west)
when it is projected towards north, acceleration due to magnetic force
=
2
a
0
Therefore magnetic field
=
2
ma
0
e
0
(down)
© examsnet.com
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