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AIPMT 2014 Physics and Chemistry Paper
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© examsnet.com
Question : 28
Total: 90
A potentiometer circuit has been set up for finding the internal resistance of a given cell. The main battery used across the potentiometer wire, has an emf
2.0
V
and a negligible internal resistance. The potentiometer wire itself is
4
m
long, When the resistance R, connected across the given cell, has values of.
(i) infinity (ii)
9.5
Ω
The balancing lengths', on the potentiometer wire are found to be
3
m
and
2.85
m
, respectively. The value of internal resistance of the cell is
0.25
Ω
0.95
Ω
0.5
Ω
0.75
Ω
Validate
Solution:
Internal resistance,
r
=
(
E
−
V
V
)
R
=
(
ℓ
1
−
ℓ
2
ℓ
2
)
R
=
(
3
−
2.85
2.85
)
(
9.5
)
Ω
=
0.5
Ω
© examsnet.com
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