a + 1 > 0 and a + 1 < √ 25 − a 2 -1" class="fm-inline"> ⇒ a > − 1 and ( a + 1 ) 2 < 25 − a 2 -1" class="fm-inline"> ⇒ a > − 1 and 2 a 2 + 2 a − 24 < 0 -1" class="fm-inline"> ⇒ a > − 1 and a 2 + a − 12 < 0 -1" class="fm-inline"> ⇒ a > − 1 and ( a − 3 ) ( a + 4 ) < 0 -1" class="fm-inline"> ⇒ a > − 1 and a ∈ ( − 4 , 3 ) ∴ a ∈ ( − 1 , 3 )" >


AMU Engineering 2018 solved paper Solved Paper

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