x 2 − 3 x + 2 > 0 ⇒ x 2 − 3 x + 2 ≤ 3 4 and 0" class="fm-inline"> x 2 − 2 x − x + 2 > 0 ⇒ 4 x 2 − 12 x + 5 ≤ 0 and 0" class="fm-inline"> ( x − 2 ) ( x − 1 ) > 0 ⇒ ( 2 x − 5 ) ( 2 x − 1 ) ≤ 0 and x ∈ ( − ∞ , 1 ) ∪ ( 2 , ∞ ) x ∈ [ 1 2 , 5 2 ] and x ∈ ( − ∞ , 1 ) ∪ ( 2 , ∞ ) ∴ x ∈ [ 1 2 , 1 ) ∪ ( 2 , 5 2 ]" >
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