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AMU Engineering 2018 solved paper Solved Paper
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© examsnet.com
Question : 5
Total: 150
The relation between time
t
and distance
x
for a moving particle is
t
=
α
x
2
+
β
x
, where
α
and
beta
are constants. If
v
is the velocity at distance
x
, then the retardation of the particle is
2
α
v
3
2
β
v
3
2
α
β
v
3
2
β
2
v
2
Validate
Solution:
Given that,
t
=
α
x
2
+
β
x
Differentiating with respect to '
t
′
1
=
α
.
2
x
d
x
d
t
+
β
d
x
d
t
1
=
20
x
v
+
β
v
1
=
v
(
20
x
+
β
)
v
=
1
2
α
x
+
β
........(i)
Retardation,
a
=
−
d
v
d
t
=
−
d
d
t
(
1
2
α
x
+
β
)
=
(
−
1
(
2
α
x
+
β
)
2
)
.
(
−
2
α
d
x
d
t
)
=
1
(
20
x
+
β
)
2
.
2
α
v
From Eq. (i), we get
=
v
2
.
2
α
v
=
2
α
v
3
© examsnet.com
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