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AMU Engineering 2018 solved paper Solved Paper
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© examsnet.com
Question : 9
Total: 150
A man throws a ball of mass
3.0
k
g
with a speed of
5.0
m
∕
s
. His hand is in contact with the ball for
0.2
s
. If he throws 4 balls in 2 seconds, the average force exerted by him in 1 second is
15
N
30
N
150
N
75
N
Validate
Solution:
Given, mass of the ball,
m
=
3
k
g
,
Δ
v
=
5
m
∕
s
and the time taken the man to throw a ball,
Δ
t
=
2
4
=
0.5
s
∴
Change in momentum of the ball,
Δ
p
=
m
.
Δ
v
=
3
×
5
=
15
N
−
s
Since, we know,
Force
=
Rate of change in linear momentum
F
=
Δ
p
Δ
t
=
15
0.5
(Putting values)
=
15
5
×
10
=
30
N
© examsnet.com
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