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AMU Engineering 2019 solved paper Solved Paper
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© examsnet.com
Question : 2
Total: 150
In a Young's double slit experiment, the slit separation is
1
m
m
and the screen is
1
m
from the slit. For a monochromatic light of wavelength
500
n
m
, the distance of 3 rd minima from the central maxima is
0.50
m
m
1.25
m
m
1.50
m
m
1.75
m
m
Validate
Solution:
Given,
d
=
1
m
m
=
1
×
10
−
3
m
,
D
=
1
m
λ
=
500
n
m
=
500
×
10
−
9
m
Distance of
n
th minima from central
maxima
x
n
=
(
2
n
−
1
)
λ
2
D
d
=
(
2
×
3
−
1
)
×
500
×
10
−
9
2
×
1
1
×
10
−
3
=
2.5
×
500
×
10
−
6
=
12.5
×
10
−
4
m
=
1.25
m
m
© examsnet.com
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