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AMU Engineering 2019 solved paper Solved Paper
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© examsnet.com
Question : 41
Total: 150
A current of
10
A
is passing through a long wire which has semicircular loop of the radius
20
c
m
as shown in the figure. Magnetic field produced at the centre of the loop is
10
π
µ
T
5
π
µ
T
4
π
µ
T
2
π
µ
T
Validate
Solution:
Magnetic field produced at the centre
B
=
1
2
(
µ
0
I
2
r
)
According to question,
I
=
10
A
,
r
=
20
c
m
=
20
×
10
−
2
m
=
1
2
×
4
π
×
10
−
7
×
10
2
×
20
×
10
−
2
=
π
×
10
−
6
20
×
10
−
2
=
5
π
×
10
−
6
T
=
5
π
µ
T
© examsnet.com
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