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AMU Engineering 2020 solved paper Solved Paper
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© examsnet.com
Question : 17
Total: 150
Two stretched wires are in unison. If the tension in one of the wire is increased by
1
%
, 3beats are produced in
2
s
. The initial frequency of each wire is
150
H
z
200
H
z
300
H
z
450
H
z
Validate
Solution:
n
1
=
k
√
T
,
n
2
=
k
√
1.01
T
∵
n
2
−
n
1
=
3
2
k
(
√
1.01
T
−
√
T
)
=
1.5
k
√
T
[
(
1
+
0.01
)
1
∕
2
−
1
]
=
1.5
k
√
T
[
1
+
1
2
×
0.01
−
1
]
=
1.5
k
√
T
=
1.5
×
2
0.01
∴
n
1
=
k
√
T
=
1.5
×
2
0.01
=
300
H
z
We know that beat frequency is the difference two frequencies, i.e.
f
1
−
f
2
.
© examsnet.com
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