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AP and TS EAMCET Engineering 2020 Model Paper 1
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© examsnet.com
Question : 119
Total: 160
The near point of a hypermetropic person is 50 cm from the eye. What is the power of the lens required to enable the person to read clearly a book held at 25 cm from the eye
2D
4D
8D
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Validate
Solution:
1
f
=
1
v
−
1
u
sign convention is u are negative
∴
1
f
=
−
1
50
−
(
1
25
)
⇒
1
f
=
−
1
50
+
1
25
∴
1
f
=
−
25
+
50
25
×
50
⇒
f
=
50
c
m
P
=
100
f
⇒
P
=
100
50
=
+
2
D
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