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AP and TS EAMCET Engineering 2020 Model Paper 3
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© examsnet.com
Question : 83
Total: 160
The momentum of a body in two perpendicular directions at any time 't' are given by
P
x
=
2
t
2
+
6
and
P
y
=
3
t
2
2
+
3
. the force acting on the body at t=2 sec
5 units
2 units
10 units
15 units
Validate
Solution:
F
x
=
d
P
x
d
t
F
y
=
d
P
y
d
t
F
=
√
F
x
2
+
F
y
2
© examsnet.com
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