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AP and TS EAMCET Engineering 2020 Model Paper 3
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© examsnet.com
Question : 87
Total: 160
A simple pendulum has time period
T
1
. the point of suspension is now moved upward accroding to the relation
y
=
k
t
2
(
k
=
1
m
s
−
2
)
where 'y’ is the vertical displacement, the time period now becomes
T
2
. the ratio of
T
1
2
T
2
2
is
(
g
=
10
m
s
−
1
)
6
5
5
6
1
4
5
Validate
Solution:
y
=
K
t
2
d
2
y
d
t
2
=
2
K
(or)
a
y
=
2
m
s
−
2
(
as
K
=
1
m
s
−
2
)
T
1
=
2
π
√
1
g
and
T
2
=
2
π
√
1
g
+
a
y
∴
T
1
2
T
2
2
=
g
+
a
y
g
=
10
+
2
10
=
6
5
© examsnet.com
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