The inverse point of (-2, 3) w.r.t. the circle x2+y2−4x−6y+9=0 is the point of intersection of polar and the line joining centre (2, 3) and (-2, 3). Polar of (-2, 3) w.r.t. the circle x2+y2−4x−6y+9=0 is −2x+3y−2(x−2)−3(y+3)+9=0 −2x+3y−2x+4−3y−9+9=0 −4x+4=0 x=