A one-one (injective) function maps distinct elements of A to distinct elements of B.So we must assign to the 3 elements of A an ordered selection of 3 distinct elements out of the 5 elements of B.The first element of A has 5 choices, the second 4 choices, and the third 3 choices.Hence the number of one-one functions is 5×4×3=5P3=60.In general, if n(A)=r and n(B)=n with r≤n, the number of one-one functions is nPr.Here n=5 and r=3, so the answer is 5P3.Note that 5C3 only counts unordered selections (subsets), which would not distinguish the different assignments to the elements of A.Therefore the correct option is 5P3, i.e. option A.