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AP and TS EAMCET Medical Model Paper 1

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Question : 108

Total: 160

The magnetic field normal to the plane of coil of 'N' turns, radius 'r' carrying current 1 A at a point lying a small distance 'h' (<< r) from the centre of coil is Ba and the field at the centre of coil is Be. Then

Bc−Ba
Bc
=
2h2
3r2
Bc−Ba
Bc
=
3h2
2r2
Bc−Ba
Bc
=
3h
2r
Bc−Ba
Ba
=
3h2
2r2

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