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AP EAMCET Engineering 17 Sep 2020 Shift 1 Paper
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© examsnet.com
Question : 30
Total: 160
Let
a
,
b
and
c
be the lengths of the sides of a triangle with its opposite angles
A
,
B
and
C
respectively. If
∠
C
=
60
°
, then the value of
c
(
a
+
b
)
+
(
a
2
+
b
2
)
(
b
+
c
)
(
c
+
a
)
is
1
2
√
3
2
1
√
3
Validate
Solution:
cos
C
=
a
2
+
b
2
−
c
2
2
a
b
⇒
cos
60
∘
=
a
2
+
b
2
−
c
2
2
a
b
⇒
a
2
+
b
2
−
c
2
=
a
b
⇒
a
2
+
b
2
=
a
b
+
c
2
...(i)
Now,
c
(
a
+
b
)
+
(
a
2
+
b
2
)
(
b
+
c
)
(
c
+
a
)
=
c
a
+
b
c
+
a
b
+
c
2
b
c
+
a
b
+
c
2
+
a
c
=
1
© examsnet.com
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