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AP EAMCET Engineering 17 Sep 2020 Shift 2 Paper
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© examsnet.com
Question : 113
Total: 160
What is the phase difference between two particles
25
m
apart in a wave represented by equation
y
=
0.03
sin
(
π
[
2
t
−
0.01
x
]
)
travelling in a medium?
π
8
π
4
π
2
π
Validate
Solution:
Equation of wave is given as
y
=
0.03
sin
(
π
[
2
t
−
0.01
x
]
)
Path difference,
∆
x
=
25
m
Comparing the wave equation by
y
=
A
sin
(
ω
t
−
k
x
)
, we get
k
=
0.01
π
⇒
2
π
λ
=
0.01
π
⇒
λ
=
2
0.01
⇒
λ
=
2
×
10
2
m
∴
Phase difference,
∆
φ
=
2
π
λ
×
∆
x
=
2
π
2
×
10
2
×
25
=
π
4
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