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AP EAMCET Engineering 17 Sep 2020 Shift 2 Paper
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© examsnet.com
Question : 117
Total: 160
Using the data given below, find the height at which a communication satellite can reside.
(
G
=
6.67
×
10
−
11
N
−
m
2
kg
−
2
,
M
=
5.98
×
10
24
.
kg
,
R
=
6.4
×
10
6
m
)
35850
k
m
3585
k
m
358.5
k
m
35.85
k
m
Validate
Solution:
Given,
G
=
6.67
×
10
−
11
N
−
m
2
k
g
−
2
M
=
5.98
×
10
24
k
g
,
R
=
6.4
×
10
6
m
For communication satellite,
T
=
24
h
=
24
×
60
×
60
s
=
8.64
×
10
4
s
We know that, time period of communication satellite is given as
T
=
2
π
(
R
+
h
)
√
G
M
R
e
+
h
=
2
π
√
(
R
e
+
h
)
3
G
M
⇒
T
2
=
4
π
2
(
R
e
+
h
)
3
G
M
⇒
R
e
+
h
=
(
T
2
G
M
4
π
2
)
1
∕
3
⇒
h
=
(
T
2
G
M
4
π
2
)
1
∕
3
−
R
=
[
8.64
×
10
4
×
6.67
×
10
−
11
×
5.98
×
10
24
4
×
(
3.14
)
2
]
1
∕
3
−
6.4
×
10
6
=
42.25
×
10
6
−
6.4
×
10
6
=
35.85
×
10
6
m
=
35850
×
10
3
m
=
35850
k
m
© examsnet.com
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