Kinetic energy of photoelectrons KE=hv−hv0 ⇒ When v>v0,KE>0 So, statement 3 is correct. where, v= frequency of incident light v0= threshold frequency Now, other options will be correct when 1. Number of photoelectrons ejected from metal surface intensity of light. 2. When, $v4. When, v=v0,KE=0 the electrons will be still on the metal surface.