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AP EAMCET Engineering 20 Apr 2019 Shift 2 Paper
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© examsnet.com
Question : 111
Total: 160
A coil in the shape of an equilateral triangle of side 2 cm is suspended from a vertex such that it hangs in a vertical plane between the poles of a permanent magnet producing a horizontal magnetic field of 100 ×
10
−
3
tesla. The magnetic field is parallel to the plane of the coil. For the moment of couple acting on the coil to be 2
√
3
×
10
−
5
Nm , the current to be passed through the coil is
0.5 A
1 A
2 A
4 A
Validate
Solution:
The current to be passed through the coil can be calculated as
τ
=
M
B
τ
=
I
A
B
2
√
3
×
10
−
5
=
I
(
√
3
×
10
−
4
)
(
100
×
10
−
3
)
I
=
2
A
© examsnet.com
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